mud pump flow rate calculator manufacturer
Rig pump output, normally in volume per stroke, of mud pumps on the rig is one of important figures that we really need to know because we will use pump out put figures to calculate many parameters such as bottom up strokes, wash out depth, tracking drilling fluid, etc. In this post, you will learn how to calculate pump out put for triplex pump and duplex pump in bothOilfield and Metric Unit.
Pumps are an integral part of almost all industries today. From construction and mining to automotive and aerospace, pumps play a vital role in keeping these industries moving forward. While there are many essential parameters in pumps, one critical parameter is the pump flow rate which becomes a guiding factor for pump manufacturers.
The pump flow rate is one of the most important factors to consider when selecting a pump. It measures how much water the pump can move in a given period of time and is typically expressed in cubic meters/hour (m3/ h). If you’re looking for a pump to use in your home or business, it’s essential to know the flow rate needed to meet your needs. Otherwise, you may end up with a pump that isn’t powerful enough or one that uses more energy than necessary.
The first step is to determine what your needs are. For example, if you’re using the pump to provide water for irrigation, you’ll need to know the maximum flow rate that will be required. Once you know your needs, you can start looking for pumps that have the required flow rate, as you will now be able to give more precise directions to the pump manufacturers about your requirement.
To choose the right pump, it’s also important to consider other factors, such as pump size and efficiency. For instance, a large pump with a high flow rate may be more expensive to purchase and operate than a smaller pump with a lower flow rate. However, it may still be the better option if your water usage is consistently high or you have multiple zones in your irrigation system that need water simultaneously.
Overall, choosing the right pump for your home or business requires careful consideration of all aspects of pumping performance. With the right pump from reliable pump manufacturers, you can rest assured that you’ll always have an adequate supply of water on demand.
Pump flow rate simply refers to the volume of fluid that is moving through a pump in a given time period. There are various units through which it is measured, and they include cubic meter/hour (m3/h), litre/sec (l/s) or gallons per minute (GPM). Different pump manufacturers refer to different pump flow units.
The flow rate of a pump can be affected by several factors, including the size and type of pump, the speed at which it is operating, and the resistance of the system it is pumping into.
Pump Speed: This is the number of times the pump can complete an entire cycle in a minute and is measured in rotations per minute (rpm). The faster the pump speed, the higher the flow rate.
Pump Size: Larger pumps can move more liquid than smaller pumps. This is why it’s essential to choose an appropriately sized pump for your application.
Liquid Density: Heavier liquids (such as oil) will flow more slowly than lighter liquids (such as water). This is because it takes more energy to move a heavier liquid.
Liquid Viscosity: Viscous liquids (such as honey) will flow more slowly than non-viscous liquids (such as water). This is because it takes more energy to move a viscous liquid.
Pipe Size: The larger the pipe diameter, the higher the flow rate. This is because there is less resistance to flow when there is a larger diameter pipe.
Pipe Length: The shorter the length of the pipe, the higher the flow rate. This is because there is less resistance to flow when there is a shorter length of pipe.
Pipe Bends: The fewer the number of bends in the pipe, the higher the flow rate. This is because there is less resistance to flow when there are fewer bends in the pipe.
Now that you know the basics of pump flow rate, you can begin to select a pump that is appropriate for your application. Keep in mind that the factors listed above will all affect pump flow rate, so it’s essential to consider each one when you give your requirements to the pump manufacturers.
Pump speed is measured in revolutions per minute (rpm). To convert from rpm to hertz, divide by 60. For example, if a pump operates at 1000 rpm, its frequency would be 16.67 Hz.
Let’s say you have a pump that is operating at 1000 rpm, has an impeller size of 6 inches, and is pumping water with a density of 62.4 lb/ft3. So the flow rate would be:
The good news is that there are many online flow rate calculators available for free, which you can consider using if you do want to get into too much mathematics.
There are a few key ways to increase the flow rate efficiency in pumps. One is to choose the right pump for the application. Another way is to ensure that the pump is sized correctly for the application. Additionally, regular maintenance can help keep a pump operating at peak efficiency.
When choosing a pump, it is vital to consider the application’s specific needs. For example, if a pump is handling a corrosive fluid, you should select stainless steel or other corrosion-resistant models. Similarly, if the fluid being pumped will be unusually viscous, then a positive displacement pump may be the best option.
Ensuring that a pump is appropriately sized for its application is also critical to maximizing flow rate efficiency. If a pump is too small for the task at hand, it will have to work much harder and will be less efficient. On the other hand, if a pump is too large for the application, it will not operate at peak efficiency.
Finally, regular maintenance is essential to keeping a pump operating at its best. This includes things like inspecting and cleaning the pump regularly and making sure that all of the moving parts are adequately lubricated. By taking these steps, it is possible to keep a pump running at peak efficiency for many years.
Oil and Gas drilling process - Pupm output for Triplex and Duplex pumpsTriplex Pump Formula 1 PO, bbl/stk = 0.000243 x ( in) E.xample: Determine the pump output, bbl/stk, at 100% efficiency for a 7" by 12". triplex pump: PO @ 100%,= 0.000243 x 7 x12 PO @ 100% = 0.142884bbl/stk Adjust the pump output for 95% efficiency: Decimal equivalent = 95 + 100 = 0.95 PO @ 95% = 0.142884bbl/stk x 0.95 PO @ 95% = 0.13574bbl/stk Formula 2 PO, gpm = [3(D x 0.7854)S]0.00411 x SPM where D = liner diameter, in. S = stroke length, in. SPM = strokes per minute Determine the pump output, gpm, for a 7" by 12". triplex pump at 80 strokes per minute: PO, gpm = [3(7 x 0.7854) 1210.00411 x 80 PO, gpm = 1385.4456 x 0.00411 x 80 PO = 455.5 gpm
Example:Duplex Pump Formula 1 0.000324 x (liner diameter, in) x ( stroke lengh, in) = ________ bbl/stk -0.000162 x (rod diameter, in) x ( stroke lengh, in) = ________ bbl/stk Pump out put @ 100% eff = ________bbl/stk Example: Determine the output, bbl/stk, of a 5 1/2" by 14" duplex pump at 100% efficiency. Rod diameter = 2.0": 0.000324 x 5.5 x 14 = 0.137214bbl/stk -0.000162 x 2.0 x 14 = 0.009072bbl/stk Pump output @ 100% eff. = 0.128142bbl/stk Adjust pump output for 85% efficiency: Decimal equivalent = 85 100 = 0.85 PO@85%)= 0.128142bbl/stk x 0.85 PO@ 85% = 0.10892bbl/stk Formula 2
PO. bbl/stk = 0.000162 x S[2(D) - d] where S = stroke length, in. D = liner diameter, in. d = rod diameter, in. Example: Determine the output, bbl/stk, of a 5 1/2". by 14". duplex pump @ 100% efficiency. Rod diameter = 2.0in.: PO@100%=0.000162 x 14 x [ 2 (5.5) - 2 ] PO @ 100%)= 0.000162 x 14 x 56.5 PO@ 100%)= 0.128142bbl/stk Adjust pump output for 85% efficiency: PO@85%,= 0.128142bb/stkx 0.85 PO@8.5%= 0.10892bbl/stk Metric calculation Pump output, liter/min = pump output. liter/stk x pump speed, spm. S.I. units calculation Pump output, m/min = pump output, liter/stk x pump speed, spm. Mud Pumps Mud pumps drive the mud around the drilling system. Depending on liner size availability they can be set up to provide high pressure and low flow rate, or low pressure and high flow rate. Analysis of the application and running the Drill Bits hydraulics program will indicate which liners to recommend. Finding the specification of the mud pumps allows flow rate to be calculated from pump stroke rate, SPM. Information requiredo Pump manufacturer o Number of pumps o Liner size and gallons per revolution Weight As a drill bit cutting structure wears more weight will be required to achieve the same RoP in a homogenous formation. PDC wear flats, worn inserts and worn milled tooth teeth will make the bit drill less efficiently. Increase weight in increments of 2,000lbs approx. In general, weight should be applied before excessive rotary speed so that the cutting structure maintains a significant depth of cut to stabilise the bit and prevent whirl. If downhole weight measurements are available they can be used in combination with surface measurements to gain a more accurate representation of what is happening in the well bore.
When it comes to pumping terminology, one crucial term to know is GPM — a measurement that will help you determine if you’re choosing the right pump. So what is GPM, and how do you calculate it?
GPM stands for gallons per minute and is a measurement of how many gallons a pump can move per minute. It is also referred to as flow rate. GPM is variable based on another measurement known as the Head, which refers to the height the water must reach to get pumped through the system. It is also referred to as flow rate. GPM is variable based on another measurement known as the Head, which refers to the height the water must reach to get pumped through the system.
Pumps are typically measured by their GPM at a certain Head measurement. For example, a pump specification may read 150 GPM at 50 Feet of Head, which means the pump will work at 150 gallons per minute when pumping water at a height of 50 feet.
The GPM formula is 60 divided by the number of seconds it takes to fill a one gallon container. So if you took 10 seconds to fill a gallon container, your GPM measurement would be 6 GPM (60/10 seconds = 6 GPM). To most accurately calculate GPM, you use the pressure tank method and formula. For this calculation, you need to know the specifications of your pressure tank, including how many gallons it holds, the gallon drawdown and the PSI. The manufacturer specifies the gallon drawdown. Once you have that information, as well as a stopwatch to keep time, follow these steps:
For example, if it took four minutes for the pressure switch to turn off, and your gallon drawdown was 20 gallons, this would mean a GPM rate of five.
GPM identifies the unique capabilities of a pump so you can select the right one for your specific needs. If you need a pump for a larger public area such as a golf course, marina or lake, you will need a pump with a much higher GPM than one used for your home’s well. Plus, choosing the correct pump is essential for reducing your costs and increasing your pump’s lifespan.
At GeoForm International, we are a leading manufacturer of high-quality submersible pumps, dredges, digester packages and aerators, all of which are made in the U.S. With our pump expertise, we know just how essential GPM is in the pumping and dredging industry from how much equipment costs to how long jobs will take.
A measure of the energy per unit of time that is being expended across the bit nozzles. It is commonly calculated with the equation HHP=P*Q/1714, where P stands for pressure in pounds per square in., Q stands for flow rate in gallons per minute, and 1714 is a conversion factor necessary to yield HHP in terms of horsepower. Bit manufacturers often recommend that fluid hydraulics energy across the bit nozzles be in a particular HHP range, for example 2.0 to 7.0 HHP, to ensure adequate bit tooth and bottom-of-hole cleaning (the minimum HHP) and to avoid premature erosion of the bit itself (the maximum HHP).
The purpose of this article is to present some guidelines and simplified techniques to size pumps and piping typically used in mud systems. If unusual circumstances exist such as unusually long or complicated pipe runs or if very heavy or viscous drilling muds are used, a qualified engineer should analyze the system in detail and calculate an exact solution.
To write about pumps, one must use words that are known and well understood. For example, the label on the lefthand side of any centrifugal pump curve is Total Head Feet. What does this mean?
The simplest way to flow water is to lay a length of pipe on the level ground and connect it to a standpipe (Figure 1). Water from the standpipe will flow steadily through the pipe. It flows faster when there is greater depth of water in the standpipe. The depth of water measured down the standpipe to the pipe connection centerline is the Total Head.
Total Head remains constant for a particular pump operated at a constant speed regardless of the fluid being pumped. However, a pump’s pressure will increase as the fluid density (mud weight) increases according to the following relationship:
Note that the pump pressure almost doubled. It follows that the required pump horsepower has increased by the same percentage. If the pump required 50 HP for water service, it will require the following horsepower for 16 lb/gal mud:
To summarize, a pump’s Total Head remains constant for any fluid pumped, only the pump pressure and pump horsepower will change. Therefore, a pump motor must be sized according to the heaviest weight mud to be pumped.
In our example problem, the required desilter pressure head is 75 ft. for any mud weight. However, the pressure would be 30.3 PSIG for water or 43.6 PSIG for 12 lb mud or 58.1 PSIG for 16 lb mud. A good rule of thumb is that the required pressure (PSIG) equals 4 times the mud weight (12 LB/GAL x 4 = 48 PSIG).
Velocity Head is an expression of the energy required to accelerate the fluid from 0 FT/SEC in the suction tank up to the velocity of the fluid in the pipe.
Determine the required pressure head and flow rate. If the pump is to supply a device such as a mud mixing hopper or a desilter, consult the manufacturer’s information or sales representative to determine the optimum flow rate and pressure head required at the device. (On devices like desilters the pressure head losses downstream of the device are considered negligible and are usually disregarded.)
Select the basic pump to pump the desired flow rate. Its best to refer to a manufacturer’s pump curve for your particular pump. (See example – Figure 3).
The pump’s impeller may be machined to a smaller diameter to reduce its pressure for a given application. Refer to the manufacturer’s pump curves or manufacturer’s representative to determine the proper impeller diameter. Excessive pressure and flow should be avoided for the following reasons:
The pump must produce more than 75 FT-HD at the pump if 75 FT-HD is to be available at the desilter inlet and the pump’s capacity must be at least 800 GPM. Therefore, we should consider using one of the following pumps from the above list: 4″ x 5″ Pump 1750 RPM – 1000 GPM at 160 FT-HD; or 5″ x 6″ Pump 1750 RPM – 1200 GPM at 160 FT-HD.
The pump suction and discharge piping is generally the same diameter as the pump flange diameters. The resulting fluid velocities will then be within the recommended ranges of 4 to 10 FT/SEC for suction lines and 4 to 12 FT/
SEC for discharge lines. Circumstances may dictate that other pipe diameters be used, but remember to try to stay within the above velocity guidelines. Smaller pump discharge piping will create larger pressure drops in the piping
and the pump may not be able to pump the required amount of fluid. (For example, don’t use a 4″ discharge pipe on a 6″ x 8″ pump and expect the pump’s full fluid flow.)
6″ pipe may be used for the suction pipe since it is relatively short and straight and the pump suction is always flooded. 6″ pipe is fully acceptable for the discharge pipe and is a good choice since the desired header is probably 6″ pipe.
8″ pipe may be used for the suction pipe (V = 5.13 FT/SEC) since V is still greater than 4 FT/SEC. 8″ pipe would be preferred if the suction is long or the suction pit fluid level is low with respect to the pump.
Mud pump liner selection in today"s drilling operations seldom (at best) considers electrical implications. Perhaps, with more available useful information about the relationships between mud pump liner size and operational effects on the electrical system, certain potential problems can be avoided. The intent of this paper is to develop those relationships and show how they affect an electrical system on example SCR rigs.Introduction
There, seems to be little consideration for the relationships between liner size and demand on a rig"s engine/generator set(s). Yet, consideration for this relationship can prove to be very helpful to drillers and operators in efficiency of a rig"s electrical system. In order to develop the relationships and help drillers and operators understand the importance of each, relationships between liner size, pump speed, pump pressure, and electrical power will be developed. Only basic physical laws will be used to develop the relationships; and, once developed, the relationships are readily applied to realistic examples utilizing a mud pump manufacturer"s pump data. Finally, conclusions will be drawn from the examples.DEVELOPMENT OF RELATIONSHIPS BASIC RELATIONSHIPS
where HHP= Hydraulic horsepower, GPM = Mud pump volumetric flow rate in gallons per minute, and PST Mud pump output pressure in pounds peer square inch.
Hydraulic horsepower is reflected to the mud pump motor via a multiplier for mechanical efficiency. it follows that motor horsepower is then represented by
We provide hydraulic components & repair services for industrial applications like paper mills, saw mills, steel mills, recycling plants, oil & gas applications and mobile applications, including construction, utility, mining, agricultural and marine equipment. This includes hydraulic pumps, motors, valves, servo/prop valves, PTOs, cylinders & parts.